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This Higher GCSE scheme of work unit covers sequences in Year 10. It finds a linear nth term, then a picture-sequence rule, generates terms from a formula, finds a quadratic nth term, writes a geometric nth term, and finishes with a recurrence.
Students have to treat n as a position, not as the next jump, and they have to use ar^(n−1) rather than ar^n. Those two distinctions are what later iteration, proof and compound-growth items all use.
A student who has secured this unit:
Students should be secure with the following before beginning this unit.
n is the term’s place in the list. Writing n + 5 for 3, 8, 13, 18 describes the difference, not the position-to-term rule.
A constant first difference means linear. A constant second difference means quadratic. The n² coefficient is half of that second difference.
A geometric sequence multiplies by a constant r. Its nth term is ar^(n−1), so term 1 is a, not ar.
A recurrence gives u_(n+1) from u_n. It is not an nth term. You still need a starting value.
| Misconception | Teaching focus |
|---|---|
| Treating n as the next term, so 3, 8, 13, 18 is written as n + 5. | Ask for the 1st term from the proposed formula. If it is not 3, n has been used as a jump. |
| Using ar^n for a geometric sequence instead of ar^(n−1). | Substitute n = 1 into the proposed formula. The output has to be the first term a, not ar. |
| Stopping at the n² piece of a quadratic and ignoring the leftover linear sequence. | Take the quadratic part away from each term and find the nth term of the list that remains. |
| Mixing a recurrence with an nth term, so u_(n+1) = 2n + 1 is treated as the 2n + 1 sequence. | Ask whether the rule uses n or the previous term before any values are generated. |
| Taking the common ratio as the first difference of a geometric list. | Divide consecutive terms, rather than subtracting them, on the first geometric examples. |
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